What is the pH of a 1.0 × 10-3 M KOH solution?A.11B.10C.3.0D.4.0

To find the pH of a KOH solution, we first need to understand that KOH is a strong base, which means it completely ionizes in water to form K+ and OH- ions. The concentration of OH- ions is therefore equal to the concentration of KOH, which is 1.0 × 10^-3 M.

We can use the formula for pOH, which is -log[OH-]. Substituting the given concentration into this formula gives us:

pOH = -log(1.0 × 10^-3) = 3

Since pH and pOH are related by the equation pH + pOH = 14 (at 25 degrees Celsius), we can find the pH by subtracting the pOH from 14:

pH = 14 - pOH = 14 - 3 = 11

So, the pH of a 1.0 × 10^-3 M KOH solution is 11 (Option A).