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pH of 0.1 M KOH will be

Question

pH of 0.1 M KOH will be

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Solution

The pH of a solution can be calculated using the formula:

pH = -log[H+]

However, in the case of KOH, a strong base, we are more interested in the concentration of OH- ions. The pOH of a solution is calculated as:

pOH = -log[OH-]

Since KOH is a strong base, it will dissociate completely in water to form K+ and OH- ions. Therefore, the concentration of OH- ions will be equal to the initial concentration of KOH, which is 0.1 M.

pOH = -log[0.1] = 1

The pH and pOH of a solution are related by the equation:

pH + pOH = 14

Therefore, we can calculate the pH of the solution as:

pH = 14 - pOH = 14 - 1 = 13

So, the pH of 0.1 M KOH will be 13.

This problem has been solved

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