Analyze the following code:public class Test { public static void main(String[] args) { int[] x = new int[5]; int i; for (i = 0; i < x.length; i++) x[i] = i; System.out.println(x[i]); } } Group of answer choicesThe program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.The program displays 4.The program has a compile error because i is not defined in the last statement in the main method.The program displays 0 1 2 3 4.
Question
Analyze the following code:public class Test { public static void main(String[] args) { int[] x = new int[5]; int i; for (i = 0; i < x.length; i++) x[i] = i; System.out.println(x[i]); } } Group of answer choicesThe program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.The program displays 4.The program has a compile error because i is not defined in the last statement in the main method.The program displays 0 1 2 3 4.
Solution
The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.
Here's why:
The code is trying to create an array of integers with a size of 5, and then it assigns each element in the array a value equal to its index. The loop runs from 0 to the length of the array (5), so the values of the array after the loop are [0, 1, 2, 3, 4].
However, the problem arises in the last line of the main method where it tries to print the value of x[i]. At this point, the value of i is 5 (because the loop has finished executing), and since arrays in Java are 0-indexed, there is no element at index 5 in the array x. This causes an ArrayIndexOutOfBoundsException.
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