Analyze the following code.public class Test { public static void main(String[] args) { int[] x = new int[3]; System.out.println("x[0] is " + x[0]); } } Group of answer choicesThe program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined
Question
Analyze the following code.public class Test { public static void main(String[] args) { int[] x = new int[3]; System.out.println("x[0] is " + x[0]); } } Group of answer choicesThe program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined
Solution
The program runs fine and displays x[0] is 0.
Here's the step by step analysis:
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The code begins with the declaration of a public class named Test. This is the standard way to define a class in Java.
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Inside the Test class, a public static void main(String[] args) method is declared. This is the main method where the execution of the Java program begins.
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Inside the main method, an integer array x of size 3 is declared and instantiated. In Java, when you declare an array, its elements are automatically initialized to the default value, which is 0 for integers.
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The next line is a print statement that prints the value of the first element of the array (x[0]). Since the array elements are automatically initialized to 0, it prints "x[0] is 0".
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There are no compile errors or runtime errors in this program. The size of the array is specified when it is declared, the array elements are automatically initialized, and the array element x[0] is defined. Therefore, the program runs fine and displays "x[0] is 0".
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