What will be the output?public class Test{ public static void main(String[] args){ int[] x = new int[3]; System.out.println("x[0] is " + x[0]); }}The program has a compile error because the size of the array wasn't specified when declaring the array.The program has a runtime error because the array elements are not initialized.The program runs fine and displays x[0] is 0.The program has a runtime error because the array element x[0] is not defined.

The program runs fine and displays x[0] is 0.

Here's the step by step explanation:

1. The program starts with the declaration of the main method, which is the entry point of any Java program.

2. Inside the main method, an integer array 'x' of size 3 is declared. In Java, when an array is created, its elements are automatically initialized to the default value, which is 0 for integers.

3. The next line is a print statement that prints the value of the first element of the array (x[0]). Since the array elements are automatically initialized to 0, it prints "x[0] is 0".

4. The program does not have any compile errors or runtime errors, and the array size is specified correctly when declaring the array. Also, the array elements are initialized automatically, so there's no issue with uninitialized elements.

The program runs fine and displays x[0] is 0.

Here's the step by step explanation:

1. The program starts with the declaration of the main method, which is the entry point of any Java program.

2. Inside the main method, an integer array 'x' of size 3 is declared. In Java, when an array is created, its elements are automatically initialized to the default value, which is 0 for integers.

3. The System.out.println statement is used to print the value of the first element of the array (x[0]). Since the array elements are automatically initialized to 0, it prints "x[0] is 0".

4. The program does not have any compile errors or runtime errors, and it runs successfully to display the output.