What is the output of the following Java code?public class array{public static void main(String args[]){int []arr = {1,2,3,4,5};System.out.println(arr[5]);}}a.5b.4c.ArrayIndexOutOfBoundsExceptiond.InavlidInputException
Question
What is the output of the following Java code?public class array{public static void main(String args[]){int []arr = {1,2,3,4,5};System.out.println(arr[5]);}}a.5b.4c.ArrayIndexOutOfBoundsExceptiond.InavlidInputException
Solution 1
The output of the given Java code will be c. ArrayIndexOutOfBoundsException.
In Java, array indices start from 0. So, for an array of size 5 like in this case, the valid indices are 0 to 4. When you try to access arr[5], it's trying to access the 6th element of an array of size 5, which does not exist. Hence, it throws an ArrayIndexOutOfBoundsException.
Solution 2
The output of the given Java code will be c. ArrayIndexOutOfBoundsException.
Here's why:
In Java, array indices start from 0. So, for the array {1,2,3,4,5}, the index of 1 is 0, the index of 2 is 1, and so on. The index of 5 is 4, not 5.
When the code tries to access arr[5], it's trying to access the 6th element of the array, which does not exist. This causes an ArrayIndexOutOfBoundsException.
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