The output of the Java code will be:

```
false
true
```

Here's why:

In Java, when you compare two arrays using the `==` operator, it doesn't compare the contents of the arrays. Instead, it checks if the two references (arr1, arr2, arr3) point to the same array in memory.

1. `arr1 == arr2` returns `false` because arr1 and arr2 are two different objects in memory, even though their contents are identical.

2. `arr2 == arr3` returns `true` because arr3 was assigned to arr1, which means they are pointing to the same object in memory.

Question

The output of the Java code will be:

```
false
true
```

Here's why:

In Java, when you compare two arrays using the `==` operator, it doesn't compare the contents of the arrays. Instead, it checks if the two references (arr1, arr2, arr3) point to the same array in memory.

1. `arr1 == arr2` returns `false` because arr1 and arr2 are two different objects in memory, even though their contents are identical.

2. `arr2 == arr3` returns `true` because arr3 was assigned to arr1, which means they are pointing to the same object in memory.

Knowee AI · Accepted Answer

The output of the Java code will be:

```
false
true
```

Here's why:

In Java, when you compare two arrays using the `==` operator, it doesn't compare the contents of the arrays. Instead, it checks if the two references (arr1, arr2, arr3) point to the same array in memory.

1. `arr1 == arr2` returns `false` because arr1 and arr2 are two different objects in memory, even though their contents are identical.

2. `arr2 == arr3` returns `true` because arr3 was assigned to arr1, which means they are pointing to the same object in memory.

What is the output of the following Java code?public class ArrayComparison { public static void main(String[] args) { int[] arr1 = {1, 2, 3}; int[] arr2 = {1, 2, 3}; int[] arr3 = arr1; System.out.println(arr1 == arr2); System.out.println(arr2 == arr3); }}

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