This piece of code is written in Java. It's a nested loop that checks for duplicate elements in an array. Here's a step-by-step explanation:

1. The outer loop starts with the first element of the array (at index 0) and iterates until the second last element (arr.length-1). The variable `i` is the index of the current element in the outer loop.

2. The inner loop starts with the element next to `i` (at index i+1) and iterates until the last element of the array. The variable `j` is the index of the current element in the inner loop.

3. Inside the inner loop, it checks if the current element of the outer loop (`arr[i]`) is equal to the current element of the inner loop (`arr[j]`). It also checks if the indices `i` and `j` are not the same to avoid comparing the same element with itself.

4. If both conditions are true, it means that a duplicate element is found. The duplicate element (`arr[i]`) is then printed to the console.

So, in summary, this code prints all duplicate elements in the array.

Question

This piece of code is written in Java. It's a nested loop that checks for duplicate elements in an array. Here's a step-by-step explanation:

1. The outer loop starts with the first element of the array (at index 0) and iterates until the second last element (arr.length-1). The variable `i` is the index of the current element in the outer loop.

2. The inner loop starts with the element next to `i` (at index i+1) and iterates until the last element of the array. The variable `j` is the index of the current element in the inner loop.

3. Inside the inner loop, it checks if the current element of the outer loop (`arr[i]`) is equal to the current element of the inner loop (`arr[j]`). It also checks if the indices `i` and `j` are not the same to avoid comparing the same element with itself.

4. If both conditions are true, it means that a duplicate element is found. The duplicate element (`arr[i]`) is then printed to the console.

So, in summary, this code prints all duplicate elements in the array.

Knowee AI · Accepted Answer

This piece of code is written in Java. It's a nested loop that checks for duplicate elements in an array. Here's a step-by-step explanation:

1. The outer loop starts with the first element of the array (at index 0) and iterates until the second last element (arr.length-1). The variable `i` is the index of the current element in the outer loop.

2. The inner loop starts with the element next to `i` (at index i+1) and iterates until the last element of the array. The variable `j` is the index of the current element in the inner loop.

3. Inside the inner loop, it checks if the current element of the outer loop (`arr[i]`) is equal to the current element of the inner loop (`arr[j]`). It also checks if the indices `i` and `j` are not the same to avoid comparing the same element with itself.

4. If both conditions are true, it means that a duplicate element is found. The duplicate element (`arr[i]`) is then printed to the console.

So, in summary, this code prints all duplicate elements in the array.

What does the following piece of code do?for (int i = 0; i < arr.length-1; i++){ for (int j = i+1; j < arr.length; j++) { if( (arr[i].equals(arr[j])) && (i != j) ) { System.out.println(arr[i]); } }}

Question

Solution

Similar Questions

Upgrade your grade with Knowee