What is the output of the following program? public class Test { public static void main(String[] args) { int[][] values = {{3, 4, 5, 1}, {33, 6, 1, 2}}; int v = values[0][0]; for (int row = 0; row < values.length; row++) for (int column = 0; column < values[row].length; column++) if (v < values[row][column]) v = values[row][column]; System.out.print(v); } } Group of answer choices135633
Question
What is the output of the following program? public class Test { public static void main(String[] args) { int[][] values = {{3, 4, 5, 1}, {33, 6, 1, 2}}; int v = values[0][0]; for (int row = 0; row < values.length; row++) for (int column = 0; column < values[row].length; column++) if (v < values[row][column]) v = values[row][column]; System.out.print(v); } } Group of answer choices135633
Solution
The output of the program will be 33.
Here's the step-by-step explanation:
-
The program starts with a 2D array
valueswith two rows and four columns. -
The variable
vis initialized with the first element of the array, which is 3. -
The program then enters a nested loop, which will iterate over each element in the 2D array.
-
Inside the inner loop, there's a condition to check if the current element of the array is greater than
v. If it is,vis updated to that value. -
This process continues until all elements in the 2D array have been checked.
-
After the loops, the program prints the value of
v, which at this point holds the highest value found in the array. -
Since 33 is the highest number in the array, the output of the program will be 33.
Similar Questions
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