Analyze the following code:public class Test {   public static void main(String[] args) {     int[] x = {1, 2, 3, 4};     int[] y = x;    x = new int[2];    for (int i = 0; i < y.length; i++)      System.out.print(y[i] + " ");  }}Group of answer choicesThe program displays 0 0 3 4The program displays 0 0The program displays 0 0 0 0The program displays 1 2

Determine output:public class Test{ public static void main(String[] args){ int[] x = {1, 2, 3, 4}; int[] y = x; x = new int[2]; for(int i = 0; i < x.length; i++) System.out.print(y[i] + " "); }}

Analyze the following code:public class Test {   public static void main(String[] args) {     int[] x = new int[5];     int i;    for (i = 0; i < x.length; i++)      x[i] = i;    System.out.println(x[i]);  }}Group of answer choicesThe program displays 4.The program displays 0 1 2 3 4.The program has a compile error because i is not defined in the last statement in the main method.The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.

Analyze the following code:  public class Test {    public static void main(String[] args) {      int[] x = new int[5];      int i;     for (i = 0; i < x.length; i++)       x[i] = i;     System.out.println(x[i]);   } } Group of answer choicesThe program displays 0 1 2 3 4.The program displays 4.The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.The program has a compile error because i is not defined in the last statement in the main method.

What is the output of the programme below?public static void main(String[] args) {     int x = 0;     while (x < 10) {          if (x & 2 == 0) {               System.out.print(x + “ “);          }          x++;     }}Group of answer choices1 3 5 7 92 4 6 8 100 2 4 6 80 1 2 3 4

What is output of the following code:public class Test{ public static void main(String[] args){ int[] x = {120, 200, 016 }; for(int i = 0; i < x.length; i++) System.out.print(x[i] + " "); }