What is the output of the programme below?public static void main(String[] args) { int x = 0; while (x < 10) { if (x & 2 == 0) { System.out.print(x + “ “); } x++; }}Group of answer choices1 3 5 7 92 4 6 8 100 2 4 6 80 1 2 3 4
Question
What is the output of the programme below?public static void main(String[] args) { int x = 0; while (x < 10) { if (x & 2 == 0) { System.out.print(x + “ “); } x++; }}Group of answer choices1 3 5 7 92 4 6 8 100 2 4 6 80 1 2 3 4
Solution
The code provided will not compile because the bitwise AND operator (&) is being used on an integer and a boolean. The condition in the if statement (x & 2 == 0) is trying to perform a bitwise AND operation between 'x' and '2 == 0'. '2 == 0' will evaluate to false and Java does not allow a bitwise AND operation between an integer and a boolean.
However, if you intended to check if 'x' is even by using the bitwise AND operator with 1 (x & 1), the correct condition should be (x & 1 == 0). In this case, the output would be all even numbers between 0 and 10, which are 0 2 4 6 8.
Similar Questions
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