Use the quadratic formula to solve. Express your answer in simplest form.5, c, squared, plus, 12, c, plus, 4, equals, 05c 2 +12c+4=0
Question
Use the quadratic formula to solve. Express your answer in simplest form.5, c, squared, plus, 12, c, plus, 4, equals, 05c 2 +12c+4=0
Solution 1
To solve the quadratic equation 5c^2 + 12c + 4 = 0 using the quadratic formula, we can follow these steps:
Step 1: Identify the coefficients of the quadratic equation. In this case, the coefficient of c^2 is 5, the coefficient of c is 12, and the constant term is 4.
Step 2: Write down the quadratic formula. The quadratic formula is given by:
c = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Substitute the coefficients into the quadratic formula. In this case, a = 5, b = 12, and c = 4. Plugging these values into the quadratic formula, we get:
c = (-(12) ± √((12)^2 - 4(5)(4))) / (2(5))
Step 4: Simplify the expression inside the square root. Evaluating the expression inside the square root, we have:
c = (-12 ± √(144 - 80)) / 10
c = (-12 ± √64) / 10
c = (-12 ± 8) / 10
Step 5: Simplify the expression further. We have two possible solutions:
c1 = (-12 + 8) / 10 = -4 / 10 = -2/5
c2 = (-12 - 8) / 10 = -20 / 10 = -2
Therefore, the solutions to the quadratic equation 5c^2 + 12c + 4 = 0 are c = -2/5 and c = -2.
Solution 2
To solve the quadratic equation 5c^2 + 12c + 4 = 0 using the quadratic formula, we can follow these steps:
Step 1: Identify the coefficients of the quadratic equation. In this case, the coefficient of c^2 is 5, the coefficient of c is 12, and the constant term is 4.
Step 2: Write down the quadratic formula. The quadratic formula is given by:
c = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Substitute the coefficients into the quadratic formula. In this case, a = 5, b = 12, and c = 4. Plugging these values into the quadratic formula, we get:
c = (-12 ± √(12^2 - 4 * 5 * 4)) / (2 * 5)
Step 4: Simplify the expression inside the square root. Evaluating the expression inside the square root, we have:
c = (-12 ± √(144 - 80)) / 10 c = (-12 ± √64) / 10 c = (-12 ± 8) / 10
Step 5: Simplify the expression further. We have two possible solutions:
c1 = (-12 + 8) / 10 c1 = -4 / 10 c1 = -2/5
c2 = (-12 - 8) / 10 c2 = -20 / 10 c2 = -2
Therefore, the solutions to the quadratic equation 5c^2 + 12c + 4 = 0 are c = -2/5 and c = -2.
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