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Use the quadratic formula to solve. Express your answer in simplest form.5, c, squared, plus, 12, c, plus, 4, equals, 05c 2 +12c+4=0

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Use the quadratic formula to solve. Express your answer in simplest form.5, c, squared, plus, 12, c, plus, 4, equals, 05c 2 +12c+4=0

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Solution 1

To solve the quadratic equation 5c^2 + 12c + 4 = 0 using the quadratic formula, we can follow these steps:

Step 1: Identify the coefficients of the quadratic equation. In this case, the coefficient of c^2 is 5, the coefficient of c is 12, and the constant term is 4.

Step 2: Write down the quadratic formula. The quadratic formula is given by:

c = (-b ± √(b^2 - 4ac)) / (2a)

Step 3: Substitute the coefficients into the quadratic formula. In this case, a = 5, b = 12, and c = 4. Plugging these values into the quadratic formula, we get:

c = (-(12) ± √((12)^2 - 4(5)(4))) / (2(5))

Step 4: Simplify the expression inside the square root. Evaluating the expression inside the square root, we have:

c = (-12 ± √(144 - 80)) / 10

c = (-12 ± √64) / 10

c = (-12 ± 8) / 10

Step 5: Simplify the expression further. We have two possible solutions:

c1 = (-12 + 8) / 10 = -4 / 10 = -2/5

c2 = (-12 - 8) / 10 = -20 / 10 = -2

Therefore, the solutions to the quadratic equation 5c^2 + 12c + 4 = 0 are c = -2/5 and c = -2.

This problem has been solved

Solution 2

To solve the quadratic equation 5c^2 + 12c + 4 = 0 using the quadratic formula, we can follow these steps:

Step 1: Identify the coefficients of the quadratic equation. In this case, the coefficient of c^2 is 5, the coefficient of c is 12, and the constant term is 4.

Step 2: Write down the quadratic formula. The quadratic formula is given by:

c = (-b ± √(b^2 - 4ac)) / (2a)

Step 3: Substitute the coefficients into the quadratic formula. In this case, a = 5, b = 12, and c = 4. Plugging these values into the quadratic formula, we get:

c = (-12 ± √(12^2 - 4 * 5 * 4)) / (2 * 5)

Step 4: Simplify the expression inside the square root. Evaluating the expression inside the square root, we have:

c = (-12 ± √(144 - 80)) / 10 c = (-12 ± √64) / 10 c = (-12 ± 8) / 10

Step 5: Simplify the expression further. We have two possible solutions:

c1 = (-12 + 8) / 10 c1 = -4 / 10 c1 = -2/5

c2 = (-12 - 8) / 10 c2 = -20 / 10 c2 = -2

Therefore, the solutions to the quadratic equation 5c^2 + 12c + 4 = 0 are c = -2/5 and c = -2.

This problem has been solved

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