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Use the quadratic formula to solve. Express your answer in simplest form.6, c, squared, minus, c, minus, 15, equals, 06c 2 −c−15=0

Question

Use the quadratic formula to solve. Express your answer in simplest form.6, c, squared, minus, c, minus, 15, equals, 06c 2 −c−15=0

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Solution

The quadratic formula is used to solve equations of the form ax^2 + bx + c = 0. The formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

In this case, the equation is 6c^2 - c - 15 = 0. So, a = 6, b = -1, and c = -15.

First, calculate the value under the square root in the quadratic formula, which is b^2 - 4ac.

= (-1)^2 - 46(-15) = 1 + 360 = 361

Then, substitute a, b, and c into the quadratic formula to find the solutions for c.

c = [1 ± sqrt(361)] / (2*6) c = [1 ± 19] / 12

So, the solutions are c = 20/12 = 5/3 and c = -18/12 = -3/2.

This problem has been solved

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