Solve the equation 5, x, squared, minus, 11, x, plus, 4, equals, 05x 2 −11x+4=0 to the nearest tenth.

The given equation is a quadratic equation of the form ax^2 + bx + c = 0. The general solution for such equations is given by the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 5, b = -11, and c = 4.

Step 1: Calculate the value under the square root in the quadratic formula, which is b^2 - 4ac. = (-11)^2 - 454 = 121 - 80 = 41

Step 2: Calculate the values of x using the quadratic formula.

x = [-(-11) ± sqrt(41)] / (2*5) = [11 ± sqrt(41)] / 10

So, the solutions are:

x = (11 + sqrt(41)) / 10 and x = (11 - sqrt(41)) / 10

To the nearest tenth, these are approximately x = 1.4 and x = 0.6.