5c 2 +12c+4=0
Solution
The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In your case, a = 5, b = 12, and c = 4.
The solutions to a quadratic equation can be found using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).
Let's plug the values into the formula:
x = [-12 ± sqrt((12)^2 - 454)] / (2*5) x = [-12 ± sqrt(144 - 80)] / 10 x = [-12 ± sqrt(64)] / 10 x = [-12 ± 8] / 10
So the solutions are x = -2 and x = -0.4.
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