Balance the following combustion reaction.  (Remember to type a "1" for any blank coefficient line) C3H8 +  O2 -->  CO2 +  H2O

To balance the combustion reaction of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), follow these steps:

1. Balance the carbon (C) atoms first. There are 3 carbon atoms in C3H8 and only 1 in CO2. So, put a coefficient of 3 in front of CO2. Now, the reaction looks like this: C3H8 + O2 --> 3CO2 + H2O

2. Next, balance the hydrogen (H) atoms. There are 8 hydrogen atoms in C3H8 and only 2 in H2O. So, put a coefficient of 4 in front of H2O. Now, the reaction looks like this: C3H8 + O2 --> 3CO2 + 4H2O

3. Finally, balance the oxygen (O) atoms. There are 6 oxygen atoms in 3CO2 and 4 oxygen atoms in 4H2O, giving a total of 10 oxygen atoms on the right side of the equation. Oxygen comes in pairs (O2), so you need 5 O2 molecules to get 10 oxygen atoms. Put a coefficient of 5 in front of O2. Now, the reaction looks like this: C3H8 + 5O2 --> 3CO2 + 4H2O

So, the balanced equation for the combustion of propane is: C3H8 + 5O2 --> 3CO2 + 4H2O