Select the correct coefficients to balance the equation showing complete combustion of C5H12. ...C5H12(l)+ ...O2(g) → ...CO2(g) + ...H2O (g)

To balance the equation for the complete combustion of C5H12, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

First, let's count the number of carbon atoms. There are 5 carbon atoms on the left side (C5H12) and 1 carbon atom on the right side (CO2). To balance the carbon atoms, we need to put a coefficient of 5 in front of CO2:

C5H12(l) + ...O2(g) → 5CO2(g) + ...H2O(g)

Next, let's count the number of hydrogen atoms. There are 12 hydrogen atoms on the left side (C5H12) and 2 hydrogen atoms on the right side (H2O). To balance the hydrogen atoms, we need to put a coefficient of 6 in front of H2O:

C5H12(l) + ...O2(g) → 5CO2(g) + 6H2O(g)

Finally, let's count the number of oxygen atoms. There are 2 oxygen atoms in each CO2 molecule and 1 oxygen atom in each H2O molecule. On the left side, we have an unknown number of O2 molecules. To balance the oxygen atoms, we need to have the same number of oxygen atoms on both sides. Since we have 5 CO2 molecules (with a total of 10 oxygen atoms) and 6 H2O molecules (with a total of 6 oxygen atoms), we need a total of 16 oxygen atoms on the left side. This means we need 8 O2 molecules:

C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(g)

Therefore, the balanced equation for the complete combustion of C5H12 is:

C5H12(l) + 8O2(g) → 5CO2(g) + 6H2O(g)