An unbalanced equation for the combustion of octane (C8H18) is shown below.Determine the whole number coefficient of the oxygen in the balanced equation. ____C8H18(g) +O2(g) → ____CO2(g) + ____H2O(l)
Question
An unbalanced equation for the combustion of octane (C8H18) is shown below.Determine the whole number coefficient of the oxygen in the balanced equation. ____C8H18(g) +O2(g) → ____CO2(g) + ____H2O(l)
Solution
To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides of the equation.
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Start by balancing the carbon (C) atoms. There are 8 C atoms in C8H18, so you need 8 CO2 on the right side to balance the C atoms. This gives us:
C8H18(g) + O2(g) → 8CO2(g) + H2O(l)
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Next, balance the hydrogen (H) atoms. There are 18 H atoms in C8H18, so you need 9 H2O on the right side to balance the H atoms. This gives us:
C8H18(g) + O2(g) → 8CO2(g) + 9H2O(l)
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Finally, balance the oxygen (O) atoms. There are 25 O atoms on the right side (16 from CO2 and 9 from H2O), so you need 12.5 O2 on the left side to balance the O atoms. However, we need a whole number, so we multiply the entire equation by 2 to get rid of the fraction:
2C8H18(g) + 25O2(g) → 16CO2(g) + 18H2O(l)
So, the whole number coefficient of the oxygen (O2) in the balanced equation is 25.
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