What will be the output of the following pseudocode?Integer p, q, r, s Set p=1, q = 1for (each r from 0 to 2 ) for (each s from -4 to -2 ) p = p + 2if(p > r) Continue End if p = 1if(p > s) Jump out of the loop End if End for End for Print p + qQuestion 80AnswerA.20B.24C.35D.13
Question
What will be the output of the following pseudocode?Integer p, q, r, s Set p=1, q = 1for (each r from 0 to 2 ) for (each s from -4 to -2 ) p = p + 2if(p > r) Continue End if p = 1if(p > s) Jump out of the loop End if End for End for Print p + qQuestion 80AnswerA.20B.24C.35D.13
Solution
The pseudocode starts by setting p and q to 1. Then it enters a nested loop where r ranges from 0 to 2 and s ranges from -4 to -2. In each iteration of the inner loop, p is incremented by 2. If p is greater than r, the loop continues without resetting p to 1. If p is greater than s, the loop is exited. After the loops, p + q is printed.
Let's go through the loops:
- For r = 0, s = -4, p becomes 3. Since p > r, it continues. Since p > s, it jumps out of the loop.
- For r = 1, s = -4, p becomes 5. Since p > r, it continues. Since p > s, it jumps out of the loop.
- For r = 2, s = -4, p becomes 7. Since p is not greater than r, it resets p to 1. Since p is not greater than s, it does not jump out of the loop.
So, at the end of the loops, p is 1 and q is 1. Therefore, the output of the pseudocode is 1 + 1 = 2. However, this option is not available in the provided choices (A.20, B.24, C.35, D.13). There might be a mistake in the question or the provided choices.
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Time leftShowQuestion 80Not yet answeredMarked out of 1.00Flag questionTipsQuestion textWhat will be the output of the following pseudocode?Integer p, q, r, s Set p=1, q = 1for (each r from 0 to 2 ) for (each s from -4 to -2 ) p = p + 2if(p > r) Continue End if p = 1if(p > s) Jump out of the loop End if End for End for Print p + qQuestion 80AnswerA.20B.24C.35D.13
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