What will be the output of the following pseudocode?Integer p, q, r Set p = 0, q = 4, r = 3 If(p || r) If(p && r) p = p &r End If p = p ^ r End If Print p + q + rQuestion 90AnswerA.20B.10C.12D.7
Question
What will be the output of the following pseudocode?Integer p, q, r Set p = 0, q = 4, r = 3 If(p || r) If(p && r) p = p &r End If p = p ^ r End If Print p + q + rQuestion 90AnswerA.20B.10C.12D.7
Solution
The pseudocode can be broken down as follows:
- Initialize p = 0, q = 4, r = 3
- Check if p or r is true. Since p is 0 (which is considered false in boolean context) and r is 3 (which is considered true), the condition is true and we enter the if block.
- Inside the if block, check if p and r is true. Since p is 0 (false) and r is 3 (true), the condition is false and we skip the inner if block.
- Still inside the outer if block, we perform the bitwise XOR operation on p and r. Since p is 0 and r is 3, the result is 3. So, p is now 3.
- Finally, we print the sum of p, q, and r. Since p is 3, q is 4, and r is 3, the sum is 10.
So, the output of the pseudocode will be 10. Therefore, the answer is B.10.
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