Let's break down the pseudo code:

1. Integer p,q,r
2. Set p=6, q=6, r=4
3. if(r

Question

Let's break down the pseudo code:

1. Integer p,q,r
2. Set p=6, q=6, r=4
3. if(r<p ||  (p-r)< (q+p))

Here, r is less than p (4<6) and (p-r) is less than (q+p) (2<16), so the condition is true. Therefore, we enter the if block.

4. p=(p+9)+p

Here, p is updated to (6+9)+6 = 21.

5. if((4^q^9)<(9^4))

This is a bit tricky because the "^" operator could mean either "to the power of" or "bitwise XOR" depending on the language. However, in most languages, "^" is the bitwise XOR operator. So, 4 XOR 6 XOR 9 = 11, and 9 XOR 4 = 13. Since 11 is not less than 13, this condition is false, so we skip this if block.

6. p=2+r (This line is skipped because the condition in step 5 is false)

7. End if (End of the inner if block)

8. p=(p+9)+q

Here, p is updated to (21+9)+6 = 36.

9. End if (End of the outer if block)

10. Print p+q+r

Finally, we print the sum of p, q, and r, which is 36+6+4 = 46.

So, the output of the pseudo code will be 46.

Knowee AI · Accepted Answer