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What will be the output of the following pseudocode?Integer p, q, rset p= 1, q= 1, r= 2q = p - 1q = r - 1if (p + 2 > q -6)if (q+2 > p- 6)p = 2end ifq= 2if (r> 5)p = qend ifend ifprintf p + q + r

Question

What will be the output of the following pseudocode?Integer p, q, rset p= 1, q= 1, r= 2q = p - 1q = r - 1if (p + 2 > q -6)if (q+2 > p- 6)p = 2end ifq= 2if (r> 5)p = qend ifend ifprintf p + q + r

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Solution

The pseudocode provided can be broken down into the following steps:

  1. Initialize three integers p, q, r with values 1, 1, 2 respectively.
  2. Set q to p - 1, which makes q = 0.
  3. Set q to r - 1, which makes q = 1.
  4. Check if (p + 2 > q - 6), which is true because (1 + 2 > 1 - 6) is true.
  5. Inside this if block, check if (q + 2 > p - 6), which is also true because (1 + 2 > 1 - 6) is true.
  6. Inside this if block, set p to 2.
  7. Set q to 2.
  8. Check if (r > 5), which is false because (2 > 5) is false. So, p is not set to q.
  9. Finally, print the sum of p, q, and r.

So, the output of the pseudocode will be 2 (value of p) + 2 (value of q) + 2 (value of r) = 6.

This problem has been solved

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