What will be the output of the following pseudocode?Integer a, b, cSet a = 1, b = 1for(each c from 4 to 7)            if(a > c )                        a = a - 1                        Jump out of the loop            Else                        a = a + c                        if(c)                                    a = a + 1                        End if            End if End for Print a + b[Note: If(x) gets executed if the value inside if(), i.e., x is not zero.]

The pseudocode initializes two variables a and b to 1. Then it enters a loop where it iterates over the values 4 to 7 (inclusive) for the variable c.

In the first iteration, c is 4. The condition a > c is false because a is 1 and c is 4. So, it goes to the else part where it adds c to a, making a = 1 + 4 = 5. Then it checks if c is not zero, which is true because c is 4. So, it increments a by 1, making a = 5 + 1 = 6.

In the second iteration, c is 5. The condition a > c is false because a is 6 and c is 5. So, it goes to the else part where it adds c to a, making a = 6 + 5 = 11. Then it checks if c is not zero, which is true because c is 5. So, it increments a by 1, making a = 11 + 1 = 12.

In the third iteration, c is 6. The condition a > c is false because a is 12 and c is 6. So, it goes to the else part where it adds c to a, making a = 12 + 6 = 18. Then it checks if c is not zero, which is true because c is 6. So, it increments a by 1, making a = 18 + 1 = 19.

In the fourth and final iteration, c is 7. The condition a > c is false because a is 19 and c is 7. So, it goes to the else part where it adds c to a, making a = 19 + 7 = 26. Then it checks if c is not zero, which is true because c is 7. So, it increments a by 1, making a = 26 + 1 = 27.

After the loop, it prints the sum of a and b, which is 27 + 1 = 28. So, the output of the pseudocode is 28.