What will be the output of the following pseudocode?Integer a, b, cset a= 1, b= 5for (each c from 6 to 7)a = a & ca = a + cend forprint a + b[ Note- & bitwise AND - The bitwise AND operator ( & ) compares each bit of the first operand to the corresponding bit of the second operand if both bits are 1 the corresponding result bit is set to 1. otherwise, the corresponding result bit is set to 0]
Question
What will be the output of the following pseudocode?Integer a, b, cset a= 1, b= 5for (each c from 6 to 7)a = a & ca = a + cend forprint a + b[ Note- & bitwise AND - The bitwise AND operator ( & ) compares each bit of the first operand to the corresponding bit of the second operand if both bits are 1 the corresponding result bit is set to 1. otherwise, the corresponding result bit is set to 0]
Solution
The pseudocode provided is a simple loop that performs bitwise AND operation and addition. Here's how it works:
- Initialize
ato 1 andbto 5. - For each
cfrom 6 to 7, do the following:- Perform a bitwise AND operation between
aandc, and assign the result back toa. - Add
ctoa, and assign the result back toa.
- Perform a bitwise AND operation between
- After the loop, add
aandb, and print the result.
Now, let's break it down:
- For
c= 6,a= 1. The binary representation of 6 is 110, and of 1 is 001. The bitwise AND operation results in 000, or 0. So,abecomes 0. Then,a=a+c= 0 + 6 = 6. - For
c= 7,a= 6. The binary representation of 7 is 111, and of 6 is 110. The bitwise AND operation results in 110, or 6. So,aremains 6. Then,a=a+c= 6 + 7 = 13. - Finally,
a+b= 13 + 5 = 18.
So, the output of the pseudocode will be 18.
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