Determine the oxidation state of each element in SF4.
Question
Determine the oxidation state of each element in SF4.
Solution
Sure, here are the steps to determine the oxidation state of each element in SF4:
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Identify the more electronegative atom: In SF4, Fluorine (F) is more electronegative than Sulfur (S).
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Assign oxidation states based on electronegativity: The oxidation state of Fluorine (F) is always -1 in compounds.
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Calculate the total oxidation state of Fluorine: Since there are 4 Fluorine atoms, the total oxidation state for Fluorine in SF4 is -1*4 = -4.
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Determine the oxidation state of Sulfur: The total charge of a neutral molecule is zero. Therefore, the oxidation state of Sulfur (S) in SF4 is +4 because +4 + (-4) = 0.
So, the oxidation state of Sulfur (S) is +4 and Fluorine (F) is -1 in SF4.
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