Determine the oxidation state of each element in Sn(HSO4)2.

Sure, here are the steps to determine the oxidation state of each element in Sn(HSO4)2:

1. Identify the oxidation state of the known elements: Hydrogen (H) is usually +1, Oxygen (O) is usually -2, and Sulfur (S) in sulfate is usually +6.

2. Use the formula for sulfate ion (SO4^2-). The total charge of the ion is -2. Since there are 4 oxygen atoms, the total charge contributed by oxygen is -8. The charge contributed by sulfur is +6. So, the total charge of the sulfate ion is -2 (-8 from oxygen +6 from sulfur).

3. In Sn(HSO4)2, there are 2 sulfate ions. So, the total charge of the sulfate ions is -4.

4. The oxidation state of tin (Sn) is the charge it must have to balance the -4 charge from the sulfate ions. Since the compound is neutral overall, the charge of tin must be +4.

So, the oxidation states are: Sn is +4, S is +6, O is -2, and H is +1.