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Determine the oxidation state of each element in Fe(HCO3)2. Fe: H:  C:  O:

Question

Determine the oxidation state of each element in Fe(HCO3)2. Fe: H:  C:  O:

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Solution

To determine the oxidation state of each element in Fe(HCO3)2, we need to understand the rules of oxidation numbers.

  1. The oxidation state of an atom in its elemental state is always zero. So, if it were just Fe, H2, C, or O2, the oxidation state would be zero. But in this compound, they are not in their elemental state.

  2. The oxidation state of a monoatomic ion is equal to its charge.

  3. Hydrogen is +1 in all compounds it forms except for those with metals where it's -1.

  4. Oxygen is usually -2 in its compounds, except in peroxides where it's -1.

  5. The sum of oxidation states in a neutral compound is zero, while in an ion it's equal to the ion's charge.

Now, let's apply these rules to Fe(HCO3)2:

  • The compound is neutral, so the sum of oxidation states is zero.

  • Hydrogen is +1.

  • Oxygen is -2.

  • The bicarbonate ion (HCO3-) is a polyatomic ion with a charge of -1. Since there are two bicarbonate ions, the total charge contributed by the bicarbonate ions is -2.

  • The oxidation state of carbon (C) is +4 in most of its compounds, including this one.

So, the oxidation states are:

Fe: +2 (because it must balance the -2 from the two bicarbonate ions)

H: +1

C: +4

O: -2

This problem has been solved

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