A piston is filled with 1.0 L of gas at a pressure of 1.0 atm. Select all outcomes that are possible if the absolute temperature of the gas doubles.Multiple select question.P becomes 2.0 atm while V remains 1.0 L.P becomes 0.5 atm while V remains 1.0 L.V becomes 4.0 L while P becomes 0.5 atm.V becomes 2.0 L while P remains 1 atm.V becomes 0.5 L while P remains 1.0 atm.
Question
A piston is filled with 1.0 L of gas at a pressure of 1.0 atm. Select all outcomes that are possible if the absolute temperature of the gas doubles.Multiple select question.P becomes 2.0 atm while V remains 1.0 L.P becomes 0.5 atm while V remains 1.0 L.V becomes 4.0 L while P becomes 0.5 atm.V becomes 2.0 L while P remains 1 atm.V becomes 0.5 L while P remains 1.0 atm.
Solution
The behavior of gases can be predicted using the ideal gas law, which states that the pressure of a gas times its volume is equal to the number of moles of the gas times the gas constant times the temperature of the gas (PV=nRT).
In this case, we are told that the absolute temperature of the gas doubles. The number of moles of gas and the gas constant remain the same, so if the temperature doubles, the product of the pressure and volume must also double.
This means that the following outcomes are possible:
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P becomes 2.0 atm while V remains 1.0 L. This is possible because the product of pressure and volume (P*V) would double from 1.0 to 2.0, matching the doubling of the temperature.
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V becomes 2.0 L while P remains 1 atm. This is possible because the product of pressure and volume (P*V) would double from 1.0 to 2.0, matching the doubling of the temperature.
The other options do not result in the product of pressure and volume doubling, so they are not possible outcomes if the absolute temperature of the gas doubles.
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