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2 pointsUsing the table Students, choose the correct SQL statement that will return the resultant table given in Figure 2.SELECT Age, Country, COUNT(*) FROM Students GROUP BY Name;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Age, Score;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Age, Country;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Score, Country;

Question

2 pointsUsing the table Students, choose the correct SQL statement that will return the resultant table given in Figure 2.SELECT Age, Country, COUNT() FROM Students GROUP BY Name;SELECT Age, Country, COUNT() FROM Students GROUP BY Age, Score;SELECT Age, Country, COUNT() FROM Students GROUP BY Age, Country;SELECT Age, Country, COUNT() FROM Students GROUP BY Score, Country;

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Solution

The correct SQL statement that will return the resultant table given in Figure 2 is:

SELECT Age, Country, COUNT(*) FROM Students GROUP BY Age, Country;

This statement will group the students by their age and country, and count the number of students in each group.

Similar Questions

Using the table Students, choose the correct SQL statement that will return the resultant table given in Figure 4.SELECT Age, Country FROM Students ORDER BY Score ASC;SELECT DISTINCT Age, Country FROM Students ORDER BY Age ASC;SELECT DISTINCT Age, Country FROM Students ORDER BY Score DESC;SELECT DISTINCT Age, Country FROM Students ORDER BY Age DESC;

Given 3 tables, students(id, name) , courses(id, name) , grades(id, course_id, student_id, grade), for each student, get all the courses that he/she is enrolled in along with the grade he/she scored for each course. Order the result by the student name in ascending order and if there is a tie, break it with the course name in ascending order and if there is a tie break it with the grade in ascending order. Your query should output a table with the following columns (name, course, grade).

Consider these following tables and only solve the query. Tables: 1) student: s_no (primary key), student_name, course_no (foreign key), age 2) courser-course-no (primary key), course-name. Query: Display all the student name, course name and also age of the students, whose age is between 23 to 27 and course having 'BCA'. Find out the students whose age is maximum.

Question 5When querying a table called Teachers that contains a list of teachers and the city they teach in, which of the following queries will return the number of teachers from each city?1 pointSELECT distinct(City) FROM Teachers SELECT City, count(City) FROM TeachersSELECT City, count(City) FROM Teachers GROUP BY CitySELECT City, distinct(City) FROM Teachers GROUP BY City6.Question 6You want to retrieve a list of employees by first name and last name for a company that are between the ages of 30 and 50. Which clause would you add to the following SQL statement: SELECTFirst_Name,Last_Name, Age FROM Company1 pointWHERE Age > 30IF Age >=30 AND Age <=50WHERE Age < 30WHERE Age >=30 AND Age <=50

Give the database schema the following tables: Student (studentId, firstName, lastName, gender, birthday, phone, address, classId) Class (classId, className) Which code snippet will display records with the following 3 columns: classId, className and amount (amount of students)?SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classId;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s WHERE c.classId = s.classIdGROUP BY c.classId, c.className;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId, c.className;

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