Consider these following tables and only solve the query. Tables: 1) student: s_no (primary key), student_name, course_no (foreign key), age 2) courser-course-no (primary key), course-name. Query: Display all the student name, course name and also age of the students, whose age is between 23 to 27 and course having 'BCA'. Find out the students whose age is maximum.

Given 3 tables, students(id, name) , courses(id, name) , grades(id, course_id, student_id, grade), for each student, get all the courses that he/she is enrolled in along with the grade he/she scored for each course. Order the result by the student name in ascending order and if there is a tie, break it with the course name in ascending order and if there is a tie break it with the grade in ascending order. Your query should output a table with the following columns (name, course, grade).

Given 3 tables, students(id, name) , courses(id, name) , grades(id, course_id, student_id, grade), find the name of the most popular course (the one with the most enrolled students and students should be passing, i.e. achieving a grade of at least 50) and if there is a tie, get the course name that's lexicographically smaller. Your query should output a table with the following columns (name)

Student Relation Student_ID   Student_Name   Dept_Name 0000 AAAAA Computer Science1111 BBBBB Computer Science2222 CCCCC  Business Administration Question 13Select one:a.CREATE TABLE Student(   Student_ID int,   Student_Name char(20),   Dept_Name char(20),);b.CREATE TABLE Student(   Student_ID int,   Student_Name varchar(100),   Dept_Name varchar(100),);c.CREATE TABLE Student(   Student_ID int,   Student_Name char(100),   Dept_Name char(100),);d.CREATE TABLE Student(   Student_ID char(20),   Student_Name char(100),   Dept_Name char(100),);

Using the table Students, choose the correct SQL statement that will return the resultant table given in Figure 4.SELECT Age, Country FROM Students ORDER BY Score ASC;SELECT DISTINCT Age, Country FROM Students ORDER BY Age ASC;SELECT DISTINCT Age, Country FROM Students ORDER BY Score DESC;SELECT DISTINCT Age, Country FROM Students ORDER BY Age DESC;

2 pointsUsing the table Students, choose the correct SQL statement that will return the resultant table given in Figure 2.SELECT Age, Country, COUNT(*) FROM Students GROUP BY Name;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Age, Score;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Age, Country;SELECT Age, Country, COUNT(*) FROM Students GROUP BY Score, Country;