Sure, here is the SQL query that you can use to get the desired output:

```sql
SELECT s.name AS name, c.name AS course, g.grade AS grade
FROM students s
JOIN grades g ON s.id = g.student_id
JOIN courses c ON c.id = g.course_id
ORDER BY s.name ASC, c.name ASC, g.grade ASC;
```

Here is the step by step explanation:

1. `FROM students s`: This is the main table we are selecting from, which contains the student information. We alias it as `s` for simplicity.

2. `JOIN grades g ON s.id = g.student_id`: We join the `grades` table on the condition that the `id` in the `students` table matches the `student_id` in the `grades` table. This allows us to connect each student with their respective grades. We alias the `grades` table as `g`.

3. `JOIN courses c ON c.id = g.course_id`: We join the `courses` table on the condition that the `id` in the `courses` table matches the `course_id` in the `grades` table. This allows us to connect each grade with the respective course. We alias the `courses` table as `c`.

4. `SELECT s.name AS name, c.name AS course, g.grade AS grade`: We select the `name` column from the `students` table, the `name` column from the `courses` table, and the `grade` column from the `grades` table. We alias these as `name`, `course`, and `grade` respectively.

5. `ORDER BY s.name ASC, c.name ASC, g.grade ASC`: We order the results first by the student's name in ascending order. If there is a tie, we then order by the course name in ascending order. If there is still a tie, we finally order by the grade in ascending order.

Question

Sure, here is the SQL query that you can use to get the desired output:

```sql
SELECT s.name AS name, c.name AS course, g.grade AS grade
FROM students s
JOIN grades g ON s.id = g.student_id
JOIN courses c ON c.id = g.course_id
ORDER BY s.name ASC, c.name ASC, g.grade ASC;
```

Here is the step by step explanation:

1. `FROM students s`: This is the main table we are selecting from, which contains the student information. We alias it as `s` for simplicity.

2. `JOIN grades g ON s.id = g.student_id`: We join the `grades` table on the condition that the `id` in the `students` table matches the `student_id` in the `grades` table. This allows us to connect each student with their respective grades. We alias the `grades` table as `g`.

3. `JOIN courses c ON c.id = g.course_id`: We join the `courses` table on the condition that the `id` in the `courses` table matches the `course_id` in the `grades` table. This allows us to connect each grade with the respective course. We alias the `courses` table as `c`.

4. `SELECT s.name AS name, c.name AS course, g.grade AS grade`: We select the `name` column from the `students` table, the `name` column from the `courses` table, and the `grade` column from the `grades` table. We alias these as `name`, `course`, and `grade` respectively.

5. `ORDER BY s.name ASC, c.name ASC, g.grade ASC`: We order the results first by the student's name in ascending order. If there is a tie, we then order by the course name in ascending order. If there is still a tie, we finally order by the grade in ascending order.

Knowee AI · Accepted Answer

Sure, here is the SQL query that you can use to get the desired output:

```sql
SELECT s.name AS name, c.name AS course, g.grade AS grade
FROM students s
JOIN grades g ON s.id = g.student_id
JOIN courses c ON c.id = g.course_id
ORDER BY s.name ASC, c.name ASC, g.grade ASC;
```

Here is the step by step explanation:

1. `FROM students s`: This is the main table we are selecting from, which contains the student information. We alias it as `s` for simplicity.

2. `JOIN grades g ON s.id = g.student_id`: We join the `grades` table on the condition that the `id` in the `students` table matches the `student_id` in the `grades` table. This allows us to connect each student with their respective grades. We alias the `grades` table as `g`.

3. `JOIN courses c ON c.id = g.course_id`: We join the `courses` table on the condition that the `id` in the `courses` table matches the `course_id` in the `grades` table. This allows us to connect each grade with the respective course. We alias the `courses` table as `c`.

4. `SELECT s.name AS name, c.name AS course, g.grade AS grade`: We select the `name` column from the `students` table, the `name` column from the `courses` table, and the `grade` column from the `grades` table. We alias these as `name`, `course`, and `grade` respectively.

5. `ORDER BY s.name ASC, c.name ASC, g.grade ASC`: We order the results first by the student's name in ascending order. If there is a tie, we then order by the course name in ascending order. If there is still a tie, we finally order by the grade in ascending order.

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