Give the database schema the following tables: Student (studentId, firstName, lastName, gender, birthday, phone, address, classId) Class (classId, className) Which code snippet will display records with the following 3 columns: classId, className and amount (amount of students)?SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classId;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s WHERE c.classId = s.classIdGROUP BY c.classId, c.className;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId, c.className;
Question
Give the database schema the following tables: Student (studentId, firstName, lastName, gender, birthday, phone, address, classId) Class (classId, className) Which code snippet will display records with the following 3 columns: classId, className and amount (amount of students)?SELECT c.classId, c.className, COUNT() AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classId;SELECT c.classId, c.className, COUNT() AS amountFROM dbo.Class c INNER JOIN dbo.Student s WHERE c.classId = s.classIdGROUP BY c.classId, c.className;SELECT c.classId, c.className, COUNT() AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId;SELECT c.classId, c.className, COUNT() AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId, c.className;
Solution
The correct code snippet to display records with the classId, className, and amount (number of students) is:
SELECT c.classId, c.className, COUNT(*) AS amount
FROM Class c
INNER JOIN Student s
ON c.classId = s.classId
GROUP BY c.classId, c.className;
Here's a step-by-step explanation:
-
SELECT c.classId, c.className, COUNT(*) AS amount: This line is selecting the columns we want to display in our result.COUNT(*) AS amountis used to count the number of students in each class. -
FROM Class c INNER JOIN Student s: This line is joining the Class table (aliased as 'c') and the Student table (aliased as 's'). -
ON c.classId = s.classId: This line is the condition for the join. It's saying that we should match records where the classId in the Class table is the same as the classId in the Student table. -
GROUP BY c.classId, c.className;: This line is grouping the results by classId and className. This is necessary because we're using an aggregate function (COUNT) and we want to get the count for each class.
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Give the database schema the following tables:Student (studentId, firstName, lastName, gender, birthday, phone, address, classId)Class (classId, className)Which code snippet will list the id and names of class with more than 15 students?SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId, c.classNameHAVING COUNT(*) > 15;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student sWHERE c.classId = s.classId AND amount > 15GROUP BY c.classId, c.className;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdGROUP BY c.classId, c.classNameHAVING amount > 15;SELECT c.classId, c.className, COUNT(*) AS amountFROM dbo.Class c INNER JOIN dbo.Student s ON c.classId = s.classIdWHERE COUNT(*) > 15;
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