To find the maximum current that can be drawn from the battery, we first need to find the total resistance of the circuit.

When resistors are combined in parallel, the total resistance (Rt) can be found using the formula:

1/Rt = 1/R1 + 1/R2

Here, R1 is 2Ω and R2 is 4Ω.

So, 1/Rt = 1/2 + 1/4 = 0.5 + 0.25 = 0.75

Therefore, Rt = 1/0.75 = 1.33Ω (approximately)

Now, we can find the maximum current using Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R).

Here, V is 16V and R is 1.33Ω.

So, I = V/R = 16/1.33 = 12.03A

Rounded off to the nearest integer, the maximum current that can be drawn from the battery is 12A.

Question

To find the maximum current that can be drawn from the battery, we first need to find the total resistance of the circuit.

When resistors are combined in parallel, the total resistance (Rt) can be found using the formula:

1/Rt = 1/R1 + 1/R2

Here, R1 is 2Ω and R2 is 4Ω.

So, 1/Rt = 1/2 + 1/4 = 0.5 + 0.25 = 0.75

Therefore, Rt = 1/0.75 = 1.33Ω (approximately)

Now, we can find the maximum current using Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R).

Here, V is 16V and R is 1.33Ω.

So, I = V/R = 16/1.33 = 12.03A

Rounded off to the nearest integer, the maximum current that can be drawn from the battery is 12A.

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