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A current of 16 amperes divides between two branches in parallel of resistances 8 ohms and 12 ohms respectively. The current in each branch is__

Question

A current of 16 amperes divides between two branches in parallel of resistances 8 ohms and 12 ohms respectively. The current in each branch is__

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Solution

To find the current in each branch, we can use the formula for calculating current in parallel circuits.

Step 1: Calculate the total resistance of the parallel circuit. In a parallel circuit, the total resistance (Rt) is given by the formula:

1/Rt = 1/R1 + 1/R2 + ...

In this case, we have two resistances: 8 ohms and 12 ohms. Plugging in the values, we get:

1/Rt = 1/8 + 1/12

Step 2: Simplify the equation by finding the common denominator:

1/Rt = (3/24) + (2/24) = 5/24

Taking the reciprocal of both sides, we get:

Rt = 24/5 = 4.8 ohms

Step 3: Use Ohm's Law to calculate the current in each branch. Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V/R

In this case, the current (I) is given as 16 amperes. We can use this information to find the voltage (V) across the parallel circuit.

Step 4: Calculate the voltage (V) using Ohm's Law:

V = I * Rt = 16 * 4.8 = 76.8 volts

Step 5: Finally, calculate the current in each branch using Ohm's Law:

For the first branch with resistance 8 ohms: I1 = V/R1 = 76.8 / 8 = 9.6 amperes

For the second branch with resistance 12 ohms: I2 = V/R2 = 76.8 / 12 = 6.4 amperes

Therefore, the current in each branch is 9.6 amperes and 6.4 amperes, respectively.

This problem has been solved

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