When a 4V battery is connected across an unknown resistor R there is a current of 100 mA in the circuit as shownin the figure. The value of the resistance of the resistor is:(a) 40 Ω(b) 4 Ω(c) 0.4 Ω(d) 400 Ω
Question
When a 4V battery is connected across an unknown resistor R there is a current of 100 mA in the circuit as shownin the figure. The value of the resistance of the resistor is:(a) 40 Ω(b) 4 Ω(c) 0.4 Ω(d) 400 Ω
Solution
To find the resistance, we can use Ohm's Law, which states that Voltage (V) = Current (I) * Resistance (R).
In this case, we know the voltage (V) is 4V and the current (I) is 100 mA, which is equivalent to 0.1 A (since 1A = 1000 mA).
Rearranging Ohm's Law to find Resistance gives us R = V/I.
Substituting the given values into the equation gives us R = 4V / 0.1A = 40 Ω.
So, the value of the resistance of the resistor is 40 Ω. Therefore, the correct answer is (a) 40 Ω.
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