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Check whether it is possible to perform the indicated operation.$\begin{bmatrix}6&-1\end{bmatrix}\begin{bmatrix}3\\2\end{bmatrix}$[6 −1][32]​ResponsesPossiblePossibleNot possibleNot possibleQuestion 2If possible, find the product. If not possible, leave the box empty.$\begin{bmatrix}6&-1\end{bmatrix}\begin{bmatrix}3\\2\end{bmatrix}=$[6 −1][32]=​

Question

Check whether it is possible to perform the indicated operation.[61][32]\begin{bmatrix}6&-1\end{bmatrix}\begin{bmatrix}3\\2\end{bmatrix}[6 −1][32]​ResponsesPossiblePossibleNot possibleNot possibleQuestion 2If possible, find the product. If not possible, leave the box empty.[61][32]=\begin{bmatrix}6&-1\end{bmatrix}\begin{bmatrix}3\\2\end{bmatrix}=[6 −1][32]=​

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Solution

The operation is possible because the number of columns in the first matrix (2 columns) is equal to the number of rows in the second matrix (2 rows). This is a requirement for matrix multiplication.

To find the product, we multiply each element of the first row of the first matrix by the corresponding element of the second matrix and then add the results:

(6 * 3) + (-1 * 2) = 18 - 2 = 16

So, the product of the two matrices is 16.

This problem has been solved

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