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Perform the indicated operations.$6\begin{bmatrix}1&3&2\\-2&4&-1\end{bmatrix}+\begin{bmatrix}5&7&-1\\6&-4&7\end{bmatrix}=$6[1 3 2−2 4 −1]+[5 7 −16 −4 7]=​

Question

Perform the indicated operations.6[132−24−1]+[57−16−47]=6\begin{bmatrix}1&3&2\\-2&4&-1\end{bmatrix}+\begin{bmatrix}5&7&-1\\6&-4&7\end{bmatrix}=6[1 3 2−2 4 −1]+[5 7 −16 −4 7]=​

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Solution

First, we need to multiply the first matrix by 6:

6[132−24−1]=[61812−1224−6]6\begin{bmatrix}1&3&2\\-2&4&-1\end{bmatrix} = \begin{bmatrix}6&18&12\\-12&24&-6\end{bmatrix}

Then, we add the resulting matrix to the second matrix:

[61812−1224−6]+[57−16−47]=[112511−6201]\begin{bmatrix}6&18&12\\-12&24&-6\end{bmatrix} + \begin{bmatrix}5&7&-1\\6&-4&7\end{bmatrix} = \begin{bmatrix}11&25&11\\-6&20&1\end{bmatrix}

So, 6[132−24−1]+[57−16−47]=[112511−6201]6\begin{bmatrix}1&3&2\\-2&4&-1\end{bmatrix}+\begin{bmatrix}5&7&-1\\6&-4&7\end{bmatrix} = \begin{bmatrix}11&25&11\\-6&20&1\end{bmatrix}

This problem has been solved

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