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Check whether it is possible to perform the indicated operation.$\begin{bmatrix}4&-3\\7&-2\end{bmatrix}-\begin{bmatrix}1&-2\\3&-6\end{bmatrix}$[4 −37 −2]−[1 −23 −6]​ResponsesPossiblePossibleNot possibleNot possibleQuestion 2If possible, find the solution. If it is not possible, leave the matrix blank.$\begin{bmatrix}4&-3\\7&-2\end{bmatrix}-\begin{bmatrix}1&-2\\3&-6\end{bmatrix}=$[4 −37 −2]−[1 −23 −6]=​

Question

Check whether it is possible to perform the indicated operation.[4372][1236]\begin{bmatrix}4&-3\\7&-2\end{bmatrix}-\begin{bmatrix}1&-2\\3&-6\end{bmatrix}[4 −37 −2]−[1 −23 −6]​ResponsesPossiblePossibleNot possibleNot possibleQuestion 2If possible, find the solution. If it is not possible, leave the matrix blank.[4372][1236]=\begin{bmatrix}4&-3\\7&-2\end{bmatrix}-\begin{bmatrix}1&-2\\3&-6\end{bmatrix}=[4 −37 −2]−[1 −23 −6]=​

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Solution

It is possible to perform the indicated operation because both matrices have the same dimensions (2x2).

To subtract matrices, we subtract corresponding elements in the matrices.

So, the solution is:

[4372][1236]=[413(2)732(6)]\begin{bmatrix}4&-3\\7&-2\end{bmatrix}-\begin{bmatrix}1&-2\\3&-6\end{bmatrix}=\begin{bmatrix}4-1&-3-(-2)\\7-3&-2-(-6)\end{bmatrix}

This simplifies to:

[3144]\begin{bmatrix}3&1\\4&4\end{bmatrix}

So, the result of the subtraction of the two matrices is the matrix [3144]\begin{bmatrix}3&1\\4&4\end{bmatrix}.

This problem has been solved

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