How much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °C? The specific heat of liquid water is 4.18 J/g°C. Round your answer to the nearest whole number. a 191 J b 11 J c 127 J d 150 J
Question
How much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °C?
The specific heat of liquid water is 4.18 J/g°C.
Round your answer to the nearest whole number.
a 191 J
b 11 J
c 127 J
d 150 J
Solution
To solve this problem, we need to use the formula for heat transfer:
q = mcΔT
where:
- q is the heat absorbed,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given:
- m = 1.5 g,
- c = 4.18 J/g°C, and
- ΔT = 30.45 °C.
Substituting these values into the formula, we get:
q = (1.5 g) * (4.18 J/g°C) * (30.45 °C) = 191.211 J
Rounding to the nearest whole number, we get 191 J.
So, the answer is (a) 191 J.
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