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How much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °C? The specific heat of liquid water is 4.18 J/g°C. Round your answer to the nearest whole number. a 191 J b 11 J c 127 J d 150 J

Question

How much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °C?

The specific heat of liquid water is 4.18 J/g°C.

Round your answer to the nearest whole number.

a 191 J

b 11 J

c 127 J

d 150 J

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Solution

To solve this problem, we need to use the formula for heat transfer:

q = mcΔT

where:

  • q is the heat absorbed,
  • m is the mass of the substance,
  • c is the specific heat capacity of the substance, and
  • ΔT is the change in temperature.

Given:

  • m = 1.5 g,
  • c = 4.18 J/g°C, and
  • ΔT = 30.45 °C.

Substituting these values into the formula, we get:

q = (1.5 g) * (4.18 J/g°C) * (30.45 °C) = 191.211 J

Rounding to the nearest whole number, we get 191 J.

So, the answer is (a) 191 J.

This problem has been solved

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