How much heat is absorbed when 15.0 g of liquid water is heated until the temperature increases by 6.0°C? The specific heat of liquid water is 4.18 J/g°C. a 376 J b 212 J c 194 J d 22 J
Question
How much heat is absorbed when 15.0 g of liquid water is heated until the temperature increases by 6.0°C? The specific heat of liquid water is 4.18 J/g°C.
a 376 J
b 212 J
c 194 J
d 22 J
Solution
The amount of heat absorbed can be calculated using the formula:
q = mcΔT
where:
- q is the heat absorbed,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given:
- m = 15.0 g,
- c = 4.18 J/g°C, and
- ΔT = 6.0°C,
we can substitute these values into the formula:
q = (15.0 g) * (4.18 J/g°C) * (6.0°C) = 376.2 J
So, the heat absorbed is approximately 376 J. Therefore, the answer is (a) 376 J.
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