Calculate the amount of heat (in J) to raise the temperature of 22.9 g of water from 4.3 o C to 31.9 oC. (Cs, water = 4.18 J/g-oC)
Question
Calculate the amount of heat (in J) to raise the temperature of 22.9 g of water from 4.3 o C to 31.9 oC. (Cs, water = 4.18 J/g-oC)
Solution
To calculate the amount of heat, we can use the formula:
q = m * Cs * ΔT
where:
- q is the heat energy,
- m is the mass of the substance,
- Cs is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
Given:
- m = 22.9 g,
- Cs = 4.18 J/g-oC, and
- ΔT = 31.9 oC - 4.3 oC = 27.6 oC.
Substituting these values into the formula, we get:
q = 22.9 g * 4.18 J/g-oC * 27.6 oC = 2627.992 J.
So, the amount of heat required to raise the temperature of 22.9 g of water from 4.3 oC to 31.9 oC is approximately 2628 J.
Similar Questions
The specific heat capacity of water is 4.184 J g -1 K -1 . Calculate the amount of heatrequired to raise the temperature of 1.00 g of water by 1.00 K
How much heat would need to be absorbed by 1.5 g of liquid water to raise its temperature by 30.45 °C? The specific heat of liquid water is 4.18 J/g°C. Round your answer to the nearest whole number. a 191 J b 11 J c 127 J d 150 J
he specific heat capacity of water is 4.2 kJ/kg°C.Calculate the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C.
How many joules of heat are required to raise the temperature of 20.0 grams of water from 30.0°C to 40.0°C?A 42 JB 84 JC 420 JD 840 J
Calculate the amount of heat required to raise the temperature of 825.8 mL of a solution from 22.4 °C to 40.4 °C if the solution has a density of 1.04 g mL–1 and a heat capacity of 4.08 J K–1 g–1.Question 1Answer63.1 kJ60.6 kJ58.3 kJ3.79 kJ
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.