Kimaya and Heena started walking from the point P at the same moment inopposite directions on a 800 m long circular path as shown below. Kimayawalked to the club house at an average speed of 100 m/min and Heenawalked to the badminton court at an average speed of 80 m/min. The lengthof the circular track between the clubhouse and the badminton court is 1802m.(Note: The figure is not to scale.)If Heena took 1 minute more than Kimaya to reach her destination, find thetime taken by Heena to reach the badminton court. Show your work.
Question
Kimaya and Heena started walking from the point P at the same moment inopposite directions on a 800 m long circular path as shown below. Kimayawalked to the club house at an average speed of 100 m/min and Heenawalked to the badminton court at an average speed of 80 m/min. The lengthof the circular track between the clubhouse and the badminton court is 1802m.(Note: The figure is not to scale.)If Heena took 1 minute more than Kimaya to reach her destination, find thetime taken by Heena to reach the badminton court. Show your work.
Solution
The problem can be solved by using the concept of relative speed and distance.
-
First, let's find the distance from point P to the clubhouse and the badminton court. Since the total length of the circular track is 800m and the distance between the clubhouse and the badminton court is 1802m, the distance from point P to the clubhouse and the badminton court is (800m - 1802m)/2 = -501m. However, distance cannot be negative, so we take the absolute value, which is 501m.
-
Now, let's find the time taken by Kimaya and Heena to reach their destinations. Since speed = distance/time, we can rearrange the formula to find time = distance/speed.
For Kimaya, time = 501m / 100m/min = 5.01 min.
For Heena, time = 501m / 80m/min = 6.26 min.
-
According to the problem, Heena took 1 minute more than Kimaya to reach her destination. So, the time taken by Heena to reach the badminton court is 5.01 min + 1 min = 6.01 min.
Therefore, Heena took approximately 6.01 minutes to reach the badminton court.
Similar Questions
From point ‘P’, Rajat walks 5m towards north. He takes right turn and walks 4m then, he takes another left turn and walks 4m. Now, after turning 135° anti-clockwise, he walks in that direction a distance of 4√2 m to reach point Q. Which of the following will be the distance between points P and Q?3 m4 mMore than 6 meters5 m
Directions for questions 7 to 9: Select the correct alternative from the given choices.Praveen leaves A at 10 a.m. and moves towards B. Akshay starts from B at 12 p.m. and moves towards A. Both met at point P, which is 200 km from B. If the speed of Praveen is twice the speed of Akshay and Praveen took 6 hours to meet Akshay, find AB.400 km600 km800 km1000 km
Jamie cycled from home to school at 7.01 a.m.. She arrived at 7.21 a.m.. Her average speed was 12 km/h. When her lessons ended, she rode home at 1.20 p.m, at an average speed which was 2 km/h slower than her initial speed. What time did she reach home?
Rajan and Madan start from a common point and walk straight in the opposite directions. What will be the distance between them at the expiry of three hours?I.Rajan and Madan walk at the speed of 4 km/hr and 6 km/hr respectively.II. Madan walks one and a half times faster than Rajan.
The following information is relevant to question 56 and 57SpeedJames leaves his house to go to his friend Mike's house. Mike's house is 3 km away from James' house and is a direct straight path. Mike also leaves his home and goes towards James’s house, however, Mike only leaves 20 minutes after James left his house. They met along the way.56Given the walking speed for both boys is 3 km/h, at what time do they meet along the way if Mike leaves at 4:30 pm?A4:50pmB4:30pmC4:40pm D5:00pm
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.