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Directions for questions 7 to 9: Select the correct alternative from the given choices.Praveen leaves A at 10 a.m. and moves towards B. Akshay starts from B at 12 p.m. and moves towards A. Both met at point P, which is 200 km from B. If the speed of Praveen is twice the speed of Akshay and Praveen took 6 hours to meet Akshay, find AB.400 km600 km800 km1000 km

Question

Directions for questions 7 to 9: Select the correct alternative from the given choices.Praveen leaves A at 10 a.m. and moves towards B. Akshay starts from B at 12 p.m. and moves towards A. Both met at point P, which is 200 km from B. If the speed of Praveen is twice the speed of Akshay and Praveen took 6 hours to meet Akshay, find AB.400 km600 km800 km1000 km

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Solution

To solve this problem, we need to understand that the distance between A and B (AB) is the sum of the distances each person traveled until they met at point P.

  1. First, we know that Praveen traveled for 6 hours at a speed that is twice that of Akshay.

  2. Since speed is distance over time, we can calculate the distance Praveen traveled. Let's denote Akshay's speed as 'x' km/h. Therefore, Praveen's speed is '2x' km/h.

  3. In 6 hours, Praveen would have traveled 6 * 2x = 12x km.

  4. We also know that they met at point P, which is 200 km from B. This is the distance Akshay traveled.

  5. Therefore, the total distance between A and B (AB) is the sum of the distances each person traveled, which is 12x + 200 km.

  6. However, we know that Akshay traveled for 2 hours less than Praveen, so in the 4 hours Akshay was traveling, he covered 200 km. Therefore, Akshay's speed 'x' is 200 km / 4 hours = 50 km/h.

  7. Substituting 'x' back into the equation for AB, we get AB = 12 * 50 km/h + 200 km = 600 km + 200 km = 800 km.

So, the correct answer is 800 km.

This problem has been solved

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