The following information is relevant to question 56 and 57SpeedJames leaves his house to go to his friend Mike's house. Mike's house is 3 km away from James' house and is a direct straight path. Mike also leaves his home and goes towards James’s house, however, Mike only leaves 20 minutes after James left his house. They met along the way.56Given the walking speed for both boys is 3 km/h, at what time do they meet along the way if Mike leaves at 4:30 pm?A4:50pmB4:30pmC4:40pm D5:00pm
Question
The following information is relevant to question 56 and 57SpeedJames leaves his house to go to his friend Mike's house. Mike's house is 3 km away from James' house and is a direct straight path. Mike also leaves his home and goes towards James’s house, however, Mike only leaves 20 minutes after James left his house. They met along the way.56Given the walking speed for both boys is 3 km/h, at what time do they meet along the way if Mike leaves at 4:30 pm?A4:50pmB4:30pmC4:40pm D5:00pm
Solution
First, let's calculate how far James will have walked by the time Mike starts walking. James starts 20 minutes before Mike, and he walks at a speed of 3 km/h. Therefore, in 20 minutes (or 1/3 of an hour), James will have walked 1 km (because 3 km/h * 1/3 h = 1 km).
This means that when Mike starts walking, the distance between them is 2 km (because Mike's house is 3 km away from James' house and James has already walked 1 km).
Now, let's calculate how long it will take for Mike to meet James. Since they are walking towards each other, their combined speed is 6 km/h (because 3 km/h + 3 km/h = 6 km/h). Therefore, to cover the remaining 2 km, it will take them 1/3 of an hour (because 2 km / 6 km/h = 1/3 h).
1/3 of an hour is 20 minutes. Therefore, if Mike leaves at 4:30 pm, they will meet 20 minutes later, at 4:50 pm.
So, the answer is A4:50pm.
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