Example 3:Solve the simultaneous equations by elimination method2 5yNote: By makingcoefficients ofone unknown inboth equations tobe the LCM ofthe givencoefficientx3 4yx 1220
Question
Example 3:Solve the simultaneous equations by elimination method2 5yNote: By makingcoefficients ofone unknown inboth equations tobe the LCM ofthe givencoefficientx3 4yx 1220
Solution
It seems like there's a formatting issue with your question. However, I'll try to solve the simultaneous equations using the elimination method.
Let's assume the equations are:
- 2x + 5y = 12
- 3x - 4y = 20
Step 1: Multiply the first equation by 4 and the second equation by 5 to make the coefficients of y the same in both equations:
- 8x + 20y = 48
- 15x - 20y = 100
Step 2: Add the two equations together:
23x = 148
Step 3: Solve for x:
x = 148 / 23 x = 6.43 (rounded to two decimal places)
Step 4: Substitute x = 6.43 into the first equation:
2(6.43) + 5y = 12 12.86 + 5y = 12 5y = 12 - 12.86 5y = -0.86 y = -0.86 / 5 y = -0.17 (rounded to two decimal places)
So, the solution to the simultaneous equations is x = 6.43 and y = -0.17.
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