Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑓−3𝑒2f−3e==33 (2)(2)𝑓+3𝑒f+3e==1515
Question
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑓−3𝑒2f−3e==33 (2)(2)𝑓+3𝑒f+3e==1515
Solution
Sure, let's solve these equations step by step:
Given equations are: 2f - 3e = 3 ----(1) f + 3e = 15 ----(2)
Step 1: Multiply equation (2) by 2, we get: 2f + 6e = 30 ----(3)
Step 2: Subtract equation (1) from equation (3), we get: 2f + 6e - (2f - 3e) = 30 - 3 9e = 27 So, e = 27/9 = 3
Step 3: Substitute e = 3 in equation (2), we get: f + 3*3 = 15 f + 9 = 15 So, f = 15 - 9 = 6
So, the solution to the given simultaneous equations is f = 6 and e = 3.
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