Calculate the solution to these simultaneous equations using the elimination method: (1)(1)𝑔+3ℎg+3h==1818 (2)(2)4𝑔+3ℎ4g+3h==3636

Sure, let's solve these equations step by step:

1. First, let's write down the equations:

   g + 3h = 18 ...(Equation 1) 4g + 3h = 36 ...(Equation 2)

2. The goal of the elimination method is to eliminate one of the variables by making the coefficients of that variable the same in both equations and then subtracting one equation from the other. In this case, the coefficients of h are already the same in both equations, so we can subtract Equation 1 from Equation 2:

   (4g + 3h) - (g + 3h) = 36 - 18 3g = 18

3. Now, we can solve for g by dividing both sides of the equation by 3:

   g = 18 / 3 g = 6

4. Now that we have the value of g, we can substitute it into Equation 1 to find the value of h:

   6 + 3h = 18 3h = 18 - 6 3h = 12

5. Finally, we can solve for h by dividing both sides of the equation by 3:

   h = 12 / 3 h = 4

So, the solution to the system of equations is g = 6 and h = 4.