Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑏−3𝑎2b−3a==88 (2)(2)𝑏+3𝑎b+3a==1313
Question
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑏−3𝑎2b−3a==88 (2)(2)𝑏+3𝑎b+3a==1313
Solution
Sure, let's solve these equations step by step:
Given equations are: 2b - 3a = 8 ...(1) b + 3a = 13 ...(2)
Step 1: Add equation (1) and equation (2) to eliminate 'a'.
This gives: 2b - 3a + b + 3a = 8 + 13 Simplifying, we get: 3b = 21
Step 2: Divide both sides by 3 to solve for 'b'.
This gives: b = 21 / 3 = 7
Step 3: Substitute b = 7 into equation (2) to solve for 'a'.
This gives: 7 + 3a = 13 Solving for 'a', we get: 3a = 13 - 7 = 6 So, a = 6 / 3 = 2
So, the solution to the system of equations is a = 2 and b = 7.
Similar Questions
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)4𝑥+𝑦4x+y==1717 (2)(2)𝑥−𝑦x−y==88
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)𝑔+3ℎg+3h==1818 (2)(2)4𝑔+3ℎ4g+3h==3636
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)𝑝+3𝑞p+3q==1414 (2)(2)4𝑝+3𝑞4p+3q==2929
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)5𝑚+𝑛5m+n==1212 (2)(2)𝑚−𝑛m−n==66
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑓−3𝑒2f−3e==33 (2)(2)𝑓+3𝑒f+3e==1515
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.