class TestArray { public static void main(String args[]) { int arr_sample[] = new int[2]; System.out.println(arr_sample[0]); }}What will be the result of compiling and executing the above code?Select one:a.The program does not compile because arr_sample[0] is being read before being initialized.b.The program compiles and prints 1 when executed.c.The program compiles and prints 0 when executed.d.The program generates a runtime exception because arr_sample[0] is being read before being initialized.e.The program compiles and runs but the results are not predictable because of un-initialized memory being read.
Question
class TestArray { public static void main(String args[]) { int arr_sample[] = new int[2]; System.out.println(arr_sample[0]); }}What will be the result of compiling and executing the above code?Select one:a.The program does not compile because arr_sample[0] is being read before being initialized.b.The program compiles and prints 1 when executed.c.The program compiles and prints 0 when executed.d.The program generates a runtime exception because arr_sample[0] is being read before being initialized.e.The program compiles and runs but the results are not predictable because of un-initialized memory being read.
Solution
The correct answer is c. The program compiles and prints 0 when executed.
Here's why:
In Java, when you declare an array, each element in the array is automatically initialized with a default value. The default value depends on the type of the array. For an array of integers, like in this case, the default value is 0.
So, when the code tries to print the value of arr_sample[0], it prints 0, because that's the default value that was automatically assigned to this element of the array when the array was declared.
Similar Questions
class ArrayTest { public static void main(String args[]) { int[] primes = new int[10]; primes[0] = "a"; System.out.println(primes[0]); }} What will be the result of compiling and executing the above code?Select one:a.Runtime exceptionb.ArrayStoreExceptionc.Compile time errord.aClear my choice
What is the result of compiling and running the following code?public class Test{ public static void main(String[] args){ int[] a = new int[0]; System.out.print(a.length); }}
Determine the output:public class Test{ public static void main(String[] args) { int[] x = new int[3]; System.out.println("x[0] is " + x[0]); }}Select one:a.The program has a runtime error because the array elements are not initialized.b.The program has a runtime error because the array element x[0] is not defined.c.The program has a compile error because the size of the array wasn't specified when declaring the array.d.The program runs fine and displays x[0] is 0.
Consider a Program:public class Test { public static void main(String[] args) { int[] numbers = {1, 2, 3, 4, 5}; for (int i = 0; i <= numbers.length; i++) { System.out.println(numbers[i]); } }}Which of the following is an output of the above program ? a. It will print numbers from 1 to 5 b. It will print numbers from 1 to 5 and then throw an exception c. It will compile but not run d. It will not compile
Given1. public class Program{2. static int i = 2;3. public static void main(String[] args) {4. int array[] = new int[i];5. array[1] = 7;6. array[2] = 8;7. System.out.print(array[1]);8. }9. } Which is true?*An Exception will be thrown at the runtime.Compilation fails as we can’t assign int values as the elements of a char array.The output will be 0.The output will be 8.The output will be 7.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.