Determine the output:public class Test{ public static void main(String[] args) { int[] x = new int[3]; System.out.println("x[0] is " + x[0]); }}Select one:a.The program has a runtime error because the array elements are not initialized.b.The program has a runtime error because the array element x[0] is not defined.c.The program has a compile error because the size of the array wasn't specified when declaring the array.d.The program runs fine and displays x[0] is 0.
Question
Determine the output:public class Test{ public static void main(String[] args) { int[] x = new int[3]; System.out.println("x[0] is " + x[0]); }}Select one:a.The program has a runtime error because the array elements are not initialized.b.The program has a runtime error because the array element x[0] is not defined.c.The program has a compile error because the size of the array wasn't specified when declaring the array.d.The program runs fine and displays x[0] is 0.
Solution
The program runs fine and displays x[0] is 0.
In Java, when you declare an array, each element is automatically initialized with a default value. For an array of integers, like in this case, the default value is 0. Therefore, even though the array elements are not explicitly initialized in the code, they are automatically initialized to 0. So, when the program tries to print the value of x[0], it successfully prints "x[0] is 0".
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